For the circuit in (Figure 1) , assume that R1 = 1.2 and R2 = 4.6 . Part A) Find
ID: 1592249 • Letter: F
Question
For the circuit in (Figure 1) , assume that R1 = 1.2 and R2 = 4.6 .
Part A) Find the rate of conversion of internal (chemical) energy to electrical energy within the battery. Express your answer in watts using two significant figures.
Part B) Find the rate of dissipation of electrical energy in the battery. Express your answer in watts using two significant figures.
Part C) Find the rate of dissipation of electrical energy in the external resistor. Express your answer in watts using two significant figures.
Explanation / Answer
total resistanc in the circuit (R) = R! + R2
R = 1.2 + 4.6 = 5.8 ohm
current in the circuit(I) = V/R = 12/5.8 = 2.068 A
A.)
rate of conversion of energy(power) = I^2 x R
= 24.82 watt
b.)power dissipiation in battery = I ^2 x R1
= 2.068^2 * 1.2
= 5.131 watt
c.)
enegy dissipiation by external resistance = I^2 X r2
= 2.068^2 X 4.6 = 19.52 watt