A RP 10 G A Car Owner Forgets : ocee -> Dwww.webassign.net/web/Student/Assignmen

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A RP 10 G A Car Owner Forgets : ocee -> Dwww.webassign.net/web/Student/Assignment-Responses/submit?dep-13097326 For this assignment, you submit answers by question parts. The number of submissions remaining for each question part only changes if you submit or change the answer Assignment Scoring Your best submission for each question part is used for your score 1. 0/4 points| Previous Answers My Notes Consider the circuit shown in the figure below. (Let R1 = 5.00 , R2 = 10.0 , and 9.00 V.) 10.0 5.00 2.00 (a) Find the voltage acrosS R1 5.64755 Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. V (b) Find the current in R1 1.12951 Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. A Submit Answer Save Progress 2. 4/4 points | Previous Answers My Notes A car owner forgets to turn off the headlights of his car while it is parked in his garage. If the 12.0-V battery in his car is rated at 41.0 A h and each headlight requires 40.2 W of power, how long will it take the battery to completely discharge? 6.1194 hours 3. +414 points | Previous Answers My Notes 7:22 PM 2/11/2016 Search the web and Windows

Explanation / Answer

First we find the equivalent resistance of circuit.

10 ohm and 5 ohm are in parralle.so

equivalent resistance of 10 ohm and 5 ohm = 5*10/(5+10) = 3.33 ohm

now equivalent resistance of 3.33ohm and R2 = 3.33 + 10 = 13.33 ohm

equivalent resistance of 13.33ohm and R1 = 13.33*5/(5+13.33) = 3.63 ohm

equivalent resistance of circuit = 3.63 + 2 = 5.63 ohm

current in circuit = V/Req = 9/5.63 = 1.6 A

now current through R1 = 1.6*13.33/(5+13.33) = 1.16 A

voltage across R1 = I*R = 1.16*5 = 5.8 volt

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