An object of charge q 1 = +1.2 C is traveling in the +x x^ direction with a spee
ID: 1595409 • Letter: A
Question
An object of charge q1 = +1.2 C is traveling in the +x x^ direction with a speed of v= 1.5 m/s in a region of magnetic field B B= + 4.1 T z z^(out of the page).
1)
In what direction is the force on q1 due to the magnetic field?
Arrow A
Into the page
Out of the page
Arrow B
Arrow C
Arrow D
Arrow E
Arrow F
Arrow G
In the direction of v v
In the opposite direction of v v
2)
What is the magnitude of the force due to the magnetic field on the object?
F = 5.22 N
F = 4.92 N
F = 7.38 N
F = 0 N
3)
An object of charge q2=-2.1 C is traveling in the (+x+y)/2(+x+y)/2 direction with an unknown speed of v in a region of magnetic field B B = 5.1 T x x^. The object q2 feels a magnetic force of magnitude 6.13 N.
In what direction is the force on q2 due to the magnetic field?
Arrow A
Into the page
Out of the page
Arrow B
Arrow C
Arrow D
Arrow E
Arrow F
Arrow G
In the direction of v v
In the opposite direction of v v
4)
What is the magnitude of the velocity of q2?
|v| = 0.572 m/s
|v| = 4.13 m/s
|v| = 2.92 m/s
|v| = 0 m/s
|v| = 0.809 m/s
5)
An object of unknown charge is traveling with speed v in the y y^ direction and enters a region with constant magnetic field B B = -5.91 T z z^ (the field points into the page). The path the object takes after entering the field is shown below.
What is the sign of the charge q3?
Positive
Negative
q3 = 0
Copyright © 2017 Freeman Worth Publishers - a division of Macmillan Learning.
About | Tech Support | Find Your Local Sales Rep | Terms Of Use | Privacy Policy
Explanation / Answer
force F= q*(v x B)
v = 1.5 i
B = 4.1 k
Fb = 1.2*( 1.5 i x 4.1 k )
Fb = 1.2*1.5*4.1 -j
Fb = -7.38 j
down wards arrow <<<------answer
=============
2)
F = 7.83 N
================
3)
Fb = q*( v x B)
Into the page
(4)
Fb = q*v*B
Fb = 2.1*v*5.1
Fb = 6.13
6.13 = 10.71*v
v = 0.572 m/s
===========
5)
Negative