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In experiment 1, the magnetic field is changed in 2.0 ms from 3.0 T to 6.0 T. In

ID: 1600390 • Letter: I

Question

In experiment 1, the magnetic field is changed in 2.0 ms from 3.0 T to 6.0 T.
In experiment 2, the magnetic field is changed in 2.0 ms from 3.0 T to 16.0 T.

courses Blackboard Learn x Magnetic field of a solenoid x Lab MI- PHYs 112 LABs (Spr x D Prelab MI.pdf Take Test Prelab MI Mag C Iowa State University of Science and Technology [US] https://bb.its.iastate.edu/bbcswebdavpid-3250123-dt-content-rid-36254724-1/courses/S2017-PHYS-1 12L-ALL/112%2... The remaining questlons refer to the following initial situation. A coil is in a region of space with a constant uniform magnetic field that is parallel to the axis of the coil Coil (side view) 3. What happens if the magnetic field is suddenly turned off? A. An EMF appears in the coil and remains there. B. An EMF appears in the coil for a very short time and then vanishes. C The EMF is ero since the magnetic field goes to zero. 4. What happens if the magnetic field is suddenly doubled? A. An EMF appears in the c and remains there. B. An EMF appears in the coil for a very short time and then vanishes. The EMF in the coil is doubled. C. Now imagine that the co is subjected to a series of experiments, that we will label 1, 2, etc., forclarity. 5. At the beginning of both experiments 1 and 2, he magnetic field is initially 3.0T. In experiment 1, the magnetic field is changed in 2.0 ms from 3.0Tto 6.0 T. In experiment 2, the magnetic field is changed in 2.0 ms from 3.0 Tto LNT What is the ratio of the average emf observed in each case, EMF1 EMF2? miskeez

Explanation / Answer

formula for average emf is

Emf 1= - A dB/ dt

= - A ( 6-3)/2* 10^-3 s

= -A ( 1.5 * 10^3 ) V

Emf 2= - A dB/ dt

= - A ( 16-3)/2* 10^-3 s

= -A ( 6.5 * 10^3 ) V

EMf1/EMf 2 = -A ( 1.5 * 10^3 ) V/-A ( 6.5 * 10^3 ) V

=0.23