In experiment 1, unpolarized light falls on the polarizer in the figure below. T

Question

In experiment 1, unpolarized light falls on the polarizer in the figure below. The angle of the analyzer is = 63.9°. In experiment 2, the unpolarized light is replaced by light of the same intensity, but the light is polarized along the direction of the polarizer's transmission axis. By how many additional degrees must the analyzer be rotated so that the light falling on the photocell will have the same intensity as it did in experiment 1? Explain whether is increased or deceased by this additional number of degrees. (Use a positive number to indicate an increase in the angle. Use a negative number to indicate a decrease in the angle.)

figure (image)

C:UsersAdministratorDownloads-figure-21.gif

Explanation / Answer

here,

let the initial intensity be I0

when unpolarized light is polarized with only one polarizer, the intensity is reduced to half the intensity of the unpolarized light

therefore , I1 = I0/2

for seccond experiment

let the angle be theta

I = I0*cos(theta)^2

0.5 = cos(theta)^2

theta = 45 degree

therefore the theta will be decreased by ( 63.9 - 45) degree

therefore the theta will be decreased by 18.9 degree

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects