In experiment 1, unpolarized light falls on the polarizer in the figure below. T
ID: 1722273 • Letter: I
Question
In experiment 1, unpolarized light falls on the polarizer in the figure below. The angle of the analyzer is 62.0 degrees. In experiment 2, the unpolarized light is replaced by light of the same intensity, but the light is polarized along the direction of the polarizer's transmission axis. By how many additional degrees must the analyzer be rotated so that the light falling on the photocell will have the same intensity as it did in experiment 1? Explain whether has increased or decreased by this additional number of degrees. (Use a positive number to indicate an increase in the angle. Use a negative number to indicate a decrease in the angle).Explanation / Answer
Given = 62o, initial intensity = I In experiment 1, the intensity on the photocell = I1 =(I/2)*cos2 In experiment 2, the intensity on the photocell = I2 =I*cos2' = (I/2)*cos2 cos2' = (1/2)*cos2 = 0.090644 cos' = 0.30107 ' = 72.5o additional angle = 72.5 - 62 = +10.5 o