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Im doing a calorimetry lab in physic, I look in the conclusions the question bei

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Question

Im doing a calorimetry lab in physic, I look in the conclusions the question being asked is

Please help out

Calorimetry Reference Cutnell & Johnson Chapter 12 Introduction A simple aluminum calorimeter will be used to determine the specific heat capacity of a solid substance, as well as the latent heat of fusion of ice. Theory The heat capacity of a substance is defined as the quantity of heat energy that must be specific transferred to unit mass of the substance to raise its temperature by one degree. is therefore measured in J/0kg he latent heat of fusion of a substance i defined as the quantity hea energy that must be transferred to a unit mass of the substance at its melting point temperature to convert it from the solid to liquid phase. The units are therefore J/kg. For both experiments, the method of mixtures will be used whereby hot materials are mixed with cold materials, and the final equilibrium temperature determined. If we assume no heat energy is transferred to or from the surroundings, the law of conservation of energy tells us: Heat energy lost by hot bodies eat energy gained by cold bodies Procedures Specific heat of aluminum. Measure the mass of the calorimeter (inner can only) plus stirrer (mo) and that of the solid aluminum rod (mA). Lower the rod into a container of boiling water. In the meantime, fill the calorimeter about full of water that has been cooled about 40C below room temperature. Re-weigh the calorimeter and hence determine the mass of water it contains Beaker of water Thermometer Hot plate Calorimeter Forceps

Explanation / Answer

Cooling the liquid below room temperature in a calorimeter before supplying the heat because this is ensures that on average heat will neither be gained nor lost to the surroundings..

Please read the theory section of your experiment, it is clearly written that we assume that no energy is transferred to or from the surrounding. so for this we cool the water initially below the room temperature.

By doing this We have also follow

heat lost by Hot body = heat gained by cool body (assuming no heat loss)