MasteringPhysics: HW11 - Google Chrome Secure | https://session.masteringphysics

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MasteringPhysics: HW11 - Google Chrome Secure | https://session.masteringphysics.com/myct/itemView?offset-next&assignmentProblemID;=77625028 Phys 2200 Help | Close HW11Exercise 31.29 Resources previous | 9 of 17 | next MasteringPhysics: HW11 - Google Chrome Secure l https://session.masteringphysics.com/myct/itemView?offset-next&assignmentProblemID;=77625029 Phys 2200 Helo Close H1 Exercise 31.32 Resources « previous | 10 of 17 | next» Exercise 31.32 Part A In an L-R-C series circuit, R= 400 , L=0.350 H and C = 0.0120 F hat is the resonance angular frequency of the circuit? rad/s Submit y Answers Give Up Part B The capacitor can withstand a peak voltage of 670 V. If the voltage source operates at the resonance frequency, what maximum voltage amplitude can it have if the maximum capacitor voltage is not exceeded? Express your answer to three significant figures and include the appropriate units. VValue Units ahie Submit My Answers Give Up ac Continue

Explanation / Answer

a)

resonance angular frequency is given as

w = 1/(sqrt(LC))

inserting the values

w = 1/(sqrt((0.350) (0.0120 x 10-6))

w = 1.54 x 104 Hz

b)

Xc = capacitive reactance = 1/wC = 1/((1.54 x 104) (0.0120 x 10-6)) = 5411.3 ohm

E = applied Voltage

i = maximum current in the circuit

maximum current is given as

i = E/R

Vc = Voltage across the capacitor = i Xc

Vc = E (Xc/R)

670 = E (5411.3/400)

E = 49.5 Volts

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