In the circuit shown, the emf is 12 volts, R_1 = 50.0 ohm, R_2 = 30.0 ohm, and L
ID: 1614799 • Letter: I
Question
In the circuit shown, the emf is 12 volts, R_1 = 50.0 ohm, R_2 = 30.0 ohm, and L = 0.500 H. For each question that follows, answer and explain your reasoning clearly. a) Switch S is closed at time t = 0. The moment just after the switch is closed: i) What is the potential difference v_cd across the inductor L? ii) Which point, c or d, is at a higher potential? iii) What is the potential difference v_ab across the resistor R_1? iv) Which point, a or b, is at a higher potential? Done in class. b) The switch is left closed for a long time and is then opened. The moment just after the switch is opened: i) What is the potential difference v_cd across the inductor L? ii) Which point, c or d, is at a higher potential? iii) What is the potential difference v_ab across the resistor R_1? iv) Which point, a or b, is at a higher potential?Explanation / Answer
1. At t=0 , inductor behave as a open circuit. So, no current will flow in Cd branch. R2 will beahve as a wire only
a) c and a will have same potential
Vcd = e =12Volt
b. c will have high potential
c. Vab=e=12volt
d. a will have high potential
2. At infinite time, Inductor behave as short circuit.
1. Vcd =0 volt
2. c and d will have same potential
3.Vab =12 volt
4. a will have high potential