In the circuit shown here, when the switch is closed the capacitor reaches a fin
ID: 1614974 • Letter: I
Question
In the circuit shown here, when the switch is closed the capacitor reaches a final charge Q_f. If the resistor is replaced by a resistor with twice the resistance, what will be the final charge on the capacitor when the switch is closed? (Assume the capacitor begins completely uncharged each time the switch is closed) a. The final charge on the capacitor will be doubled (2Q_f) b. The final charge on the capacitor will be halved (Q_f/2) c. The final charge on the capacitor will be the same (Q_f), and the capacitor's voltage will be doubled d. The final charge capacitor will be the same (Q_f), and the capacitors voltage will be halved e. The final charge on the capacitor will be the same (Q_f), and the capacitor's voltage will be the sameExplanation / Answer
Changing the value of the resistance in the circuit only changes time constant t = RC . Time contant is the time taken to reach to the maximum value of the voltage across the capacitor. But the voltage across the capacitor will not change. So charge, Q = CV will also be the same. So option e is correct.