In the circuit shown here, the two bulbs are identical and have equal brightness
ID: 1566393 • Letter: I
Question
In the circuit shown here, the two bulbs are identical and have equal brightness. How does the current through bulb A compare to the current through the battery? a. Current through A is equal to the current through the battery b. Current through A is double the current through the battery c. current through A is four times the current through the battery d. current through A is half the current through the battery e. Current through A is one-fourth the current through the battery A battery supplies 20.0 W of power when connected to a single 5 ohm resistor. A second 5 ohm resistor is connected in series to the first, and they are connected to the same battery. What is the current coming from the battery when the two resistors are connected in series? a. 2.0 A b. 4.0 A c. 1.0 A d. 10.0 A e. 40.0 A.Explanation / Answer
8. Potential diffrence through both bulb will be equal to the battery.
Va = Vb = e (parallel branchs)
Ia = Ib = e/R
current through battery = Ia + Ib = 2e/R
Ans: (D)
9. Req = 5 + 5 = 10 ohm
I = V/Req = 20 / 10 = 2 A
Ans(a)