A 60 N force is exerted on the blocks shown at right. The contact surface is fri
ID: 1622526 • Letter: A
Question
A 60 N force is exerted on the blocks shown at right. The contact surface is frictionless. Is the magnitude of the acceleration of the block at the top greater than, less than or equal to the magnitude of the acceleration of the block at the bottom? Show your work and calculate the corresponding accelerations The blocks shown at right have different mass. Is the magnitude of the net force acting on the block at the top greater than, less than or equal to the magnitude of the net force acting on the block at the bottom? Show your work. Is the magnitude of the acceleration of the block at the top greater than, less than or equal to the magnitude of the acceleration of the block at the bottom? Show your work.Explanation / Answer
solution to situation 5 depends what value do I take for gravity ( 9.8 or 10 )
If I take gravity as 10, then accleration would be equal for both blocks. however if I take gravity as 9.8 , my calculations:
a= F/m = 60/ 20 = 3 m/s^2 and for the top box ( mass = weight/ g= 200/ 9.8= 20.408 Kg)
a( for top box) = F/ m= 60/ 20.408=2.94 m/s^2
Therefore acceleration for top box is less than acceleration for bottom box
Situation 6
Net force ( top box) = 50 N - 10 N = 40 N
Net force ( bottom box) = 60 N - 40 N = 20 N
Net force is greater for top box.
a ( for top bpx) = 40/ 20 = 2 m/s^2
a ( for bottom box) = 20/ 40 = 0.5 m/s^2
accleration for top box is greater