A 6.97 kg particle moves in an xy plane. At the instant when the particle\'s pos
ID: 2255006 • Letter: A
Question
A 6.97 kg particle moves in an xy plane. At the instant when the particle's position and velocity are r =(5.00i+5.00j)m , the force on the particle is At this instant, determine (a) the particle's angular momentum about the origin, (b) the particle's angular momentum about the point x = 0, y = 5.00 m, (c) the torque acting on the particle about the origin, and (d)the torque acting on the particle about the point x = 0, y = 5.00 m. Assume counterclockwise direction positive and clockwise direction negative.Explanation / Answer
a)6.97*7.68*5
=267.648 kg m^2/s
b)torque= -(5*7.38)
=-36.9 clockwise
c)-36.9
clockwise
d)-36.9
clockwise