Refer to http://bit.ly/2uCD7KV Lab handout for answers NEWTON’S SECOND LAW Prela
ID: 1632037 • Letter: R
Question
Refer to http://bit.ly/2uCD7KV Lab handout for answers
NEWTON’S SECOND LAW Prelab Quiz
QUESTION 1
How should the acceleration be found in each trial?
a. Fit the position vs. time graph to a parabola and multiple the coefficient in front of t^2 by 2.
b. Take the reciprocal of the slope of best-fit-line of the velocity vs. time graph.
c. Take the slope of best-fit-line of the velocity vs. time graph.
d. Taking the average of the acceleration vs. time graph.
e. Fit the position vs. time graph to a parabola and dividing the coefficient in front of t^2 by 2.
QUESTION 2
How do you find the frictional force from the tension vs. acceleration graph?
a. It's equal to the slop of the best-fit line.
b. It's equal to the y-intercept of the best-fit line.
c. It's equal to the reciprocal of the slope of the best-fit line.
d. It's equal to the x-intercept of the best-fit line.
QUESTION 3
Which is correct regarding the tension in the cord?
a. T < m(H)g
b. T = m(H)g
c. T > m(H)g
QUESTION 4
Why is it important to press the tare button on the force sensor before each run?
a. The force data may be offset and not have a proper zero value
b. The sensor will get too hot and shut down
c. Who cares why it's important, I just follow instructions without thinking.
d. Capstone will not start recording until tare is pressed
QUESTION 5
How is the mass of the cart, m(c) , found from the tension vs. acceleration graph?
a. It's equal to the y-intercept of the best-fit line.
b. It's equal to the x-intercept of the best-fit line.
c. It's equal to the reciprocal of the slope of the best-fit line.
d. It's equal to the slope of the best-fit line.
Explanation / Answer
q1) option c as we are getting only velocity vs time plots the best fit line slope would give the acceleration value neglecting the initial jerks if any.
q2) T- fr = mca , where fr is the frictional force
Thus, t= ma + fr
therefore, y intercept of the graph should give the frictional force
q3) mH g - T = mc a
therefore, mH g - mc a= T
this implies, mH g >T
q4) option a
q5) equal to slope of best fit line