Please answer this question include all steps needed. Thanks worth 10 points tot
ID: 1637179 • Letter: P
Question
Please answer this question include all steps needed.Thanks worth 10 points total Feet At Possibly helpful information rz-ri +vneAt p mv AP (g 9.8 N/kg) weight mg 120.0 m/s. l. A 0.75-kilogram ball is kicked across a level field with an initial velocity of 9.00.12 It takes 0.63 seconds to reach maximum height. Neglect air resistance. (a) what is the initial momentum of the ball (write in component form. then calculate its magnitude) (b) What is the net force on the ball during its flight (n component form? (c) What is the momentum of the ball at maximum height (n component form? (d.) If the ball begins at the origin, what will be its x coordinate when the ball reaches maximum height?
Explanation / Answer
(a)
initial velocity of the ball is v = 9 m/si + 12 m/sj
initial momentum is,
P = mv = (0.75kg)(9 m/si + 12 m/sj)
or, P = (6.75i + 9j)kg-m/s.
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(b)
Net force on the ball in air is the gravitational force,
So, net force is F = -mgj
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(c)
At maximum height the vertical velocity is zero, there is only horizontal velocity. Initial horizontal velocity was along x-axis only. So velocity at maximum height will also be along x-axis. Also, there is no acceleration along x-axis so the velocity of the ball will be 9 m/s along x-axis.
So momentum at maximum height is,
P = (0.75kg)(9 m/si)
or, P = 6.75 kg-m/si
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(d)
t = 0.63 s is the time taken to reach the maximum height
So, x-coordinate at maximum height is,
x = vxt = (9m/s)(0.63 s)
or, x = 5.67 m
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