Plot 1 in Figure (a) gives the charge q that can be stored on capacitor 1 versus

Question

Plot 1 in Figure (a) gives the charge q that can be stored on capacitor 1 versus the electric potential V set up across it. The vertical scale is set by q_s = 8.0 mu C, and the horizontal scale is set by V_s = 10 V. Plots 2 and 3 are similar plots for capacitors 2 and 3, respectively. Figure (b) shows a circuit with those three capacitors and a 9.1 V battery. What is the charge stored on capacitor 2 in that circuit? The number of significant digits is set to 2: the tolerance is +/-1 in the 2nd significant digit

Explanation / Answer

slope of Q vs v will give us capacitance.

C1 = (6 qs / 8) / Vs = (6 x 8uC) / (8 x 10 V) = 0.6 uF

C2 = (0.5 x 8 ) / (10) = 0.4 uF

C3 = (0.25 x8) / 10 = 0.2 uF

C2 and C3 are in parallel connection.

C = C2 + C3 = 0.6 uF

PD across C = 9.1/2 = 4.55 Volt

C2 and C3 are in paralllel : V2 = V3 = 4.55 V

Q2 = C2 V2 = (0.4 uF)(4.55) = 1.82 uC .........Ans

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