ID: A 54. Charge A and charge B are 3.00 m apart, and charge A is +2.00 C and ch
ID: 1646814 • Letter: I
Question
ID: A 54. Charge A and charge B are 3.00 m apart, and charge A is +2.00 C and charge B is +3.00 C. Charge C is located between them at a C? a. 0.555 m b. 0.667 m c. 1.35 m d. 1.50 m certain point and the force on charge C is zero. How far from charge A is charge 55. Two equal charges, each way between the two charges so that the net force on each charge would be zero? Q, are separated by some distance. What third charge would need to be placed halt 56, A6.0 C charge is placed at the origin and a second charge is placed on the x-axis ax-030 m. If the resulting force on the second charge is 5.4 N in the positive x -direction, what is the value of its charge? a. 9.0 Hc b. 9.0 nC d. -9.0 nC A6.00 iC charge is placed at the origin and a second charge is placed on the x-axis at x-0.300 m. If the resulting force on the second charge is 6.40 N in the positive x-direction, what is the force on the charge at the origin? a. 6.40 N in the positive x-direction b. 6.40 N in the negative x-direction c. ON d. not able to be determined until the second charge is known 57 58. Two point charges are separated by 10.0 cm and have charges of +2.00 AC and -2.00 uC, respectively. What is the electric field at a point midway between the two charges? (8.99 x 10 N mIC) a. 28.8 x 10 N/C b. 14.4x 10 N/C c. 7.19 x 10 N/C d. zero 59. Charges of 4.0, C and-6.0 AC are placed at two corners of an equilateral triangle with sides of 0.10 m. At the thin coer, whatis the electric fiel magnitude created by these two charges?k-8.99 x 10 Nm/C) a. 4.5x 10 N/C b. 3.1 x 106 N/C c. 1.6 x 106 N/C d. 4.8 x 10 N/CExplanation / Answer
54. GIven Qa = 2 C
Qb = 3 C
distance between then d = 3 m
distance of charge c from A = x
now force on charge C is 0, so
kQa/x^2 = kQb/(d-x)^2
2/x^2 = 3/(d-x)^2
2(d^2 + x^2 - 2dx) = 3x^2 = 2d^2 + 2x^2 - 4dx
x^2 + 4dx - 2d^2 = 0
x^2 + 4*3x - 2*3^2 = 0
x^2 + 12x - 18 = 0
X = 1.34 M (option c)
55. let the charge placed in the center be q
then force on left charge because of twoi charges = k[q/a^2 + Q/4a^2]Q = 0
q + Q/4 = 0
q = -Q/4 ( option c)
56. valuer of charge = q
then kq*6*10^-6/0.3^2 = 5.4 N
q = 9 micro C ( option A)
57. as the forces form action reaciton pair
F = 6.4 N in -ve x direction ( option b)