Sir Lost-a-Lot dons his armor and sets out from the castle on his trusty steed (

Question

Sir Lost-a-Lot dons his armor and sets out from the castle on his trusty steed (see figure below). Usually, the drawbridge is lowed to a horizontal position so that the end of the bridge rests on the stone ledge. Unfortunately Lost-a-Lot's squire didn't lower the drawbridge far enough and stopped it at = 20.0° above the horizontal. The knight and his horse stop when their combined center of mass is d = 1.00 m from the end of the bridge. The uniform bridge is = 7.50 m long and has a mass of 2 200 kg. The lift cable is attached to the bridge 5.00 m from the hinge at the castle end and to a point on the castle wall h = 12.0 m above the bridge. Lost-a-Lot's mass combined with his armor and steed is 950 kg.

*** I got part (a) and (b) but can't seem to figure out part (c), I have 1 last attempt, please be thourough.

116 (a) Determine the tension in the cable. 26916.6 (b) Determine the horizontal force component acting on the bridge at the hinge. magnitude 11179.22 direction tothe right (c) Determine the vertical force component acting on the bridge at the hinge. magnitude magnitude 6384.73 direction upwards What forces have components in the vertical direction? N

Explanation / Answer

The net force in the vertical direction is zero.

so, Sy + Tcos20 - (m + M)g = 0

=> Sy = (2200 + 950)(9.8) - (26916.6)cos20 = 5576.67 N

and this force will be directed upwards.

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