Q_1 = +4C and Q_2 = -4C Point charges Q_1 and Q_2 are placed along the x-axis as
ID: 1649655 • Letter: Q
Question
Q_1 = +4C and Q_2 = -4C Point charges Q_1 and Q_2 are placed along the x-axis as indicated above. a) What is the net electric field at M due to Q_1 and Q_2? a) What is the force on a charge of +2.0C placed at M? c) What is the electric field at N due to Q_1 and Q_2? d) What is the force on a charge of +2.0C placed at N? e) What is the net electric potential at M due to Q_1 and Q_2? f) What is the Electric Potential Energy (EPE) of a +2C charge placed at M g) What is the electric potential at N due to Q_1 and Q_2? h) What is the Electric Potential Energy (EPE) of a +2C charge placed at N i) What is the work done by the net electric field due to Q_1 and Q_2 if a +2C charge moves from M to N? k = 1/4 pi epsilon 0 = 9 times 10^9 N.m^2/C^2Explanation / Answer
formula for electric field due to point charge is
E = kq/r^2
at point M due to Q1
E1 = kQ1/r^2 = 9 * 10^9 ( 4)/( 8)^2 = 0.5625 * 10^9 N/C
due to Q2
E2 = kQ2/ r^2 = 9 * 10^9)*( -4C)/2^2 = -9 * 10^9
net electric at point M is
E net = E1 + E2 = -8.4375 * 10^9 N/C
(b)
force on a charge + 2C at M is
F = E net Q = -8.4375 * 10^9 N/C ( 2C) = -16.875 * 10^9 N
(c)
at point N is
the electric field due to Q1 and Q2 is only horizontal components, vertical components of electric field due to Q1 and Q2 are equal and opposite so they cancel
E net = 2 E cos theta
= 2 ( kQ1/ r^2) ( 3/ sqrt ( 3^2 + 4^2) )
= 2 ( 9* 10^9 ( 4)/ ( 3^2 + 4^2) * ( 3/ sqrt ( 3^2 + 4^2) )
=1.728 * 10^9 N i
(d)
the force on a charge of 2 C placed at N is
F = Eq = 1.728 * 10^9 N i( 2) = 3.456 * 10^9 N i
As per chegg guide lines I worked first four sub parts, please post remaning parts in the next question