Masteri De https://session.masteringphysics.com/myct/itemView?assignmentProblemI

Question

Masteri De https://session.masteringphysics.com/myct/itemView?assignmentProblemID-833 1 1054 Assignment 2Problem 26.14 Mozilla Firefox « previous | 5 of 10 | next Problem 26.14 Part A Two 11-cm-diameter charged disks face each other 19 cm apart. Both disks are charged to - 80 nC What is the electric field strength between the disks, along their common axis, at the midpoint between the two disks? Express your answer as an integer and include the appropriate units. E-Vaue Units Submit My Answers Give Up Part B What is the electric field strength between the disks, along their common axis, at a point 5.0 cm from one disk? Express your answer to two significant figures and include the appropriate units. E1.48 10 Submit My Answers Give Up Incorrect; Try Again; 3 attempts remaining Continue 3:21 PM t Ask me anything

Explanation / Answer

Solution:

Here;

Diameter of each disk, D = 11 cm = 0.11 m

Radius of each disk, R = 0.055 m

Distance between the disks, d = 0.19 m

Charge of each disk, q = - 80 nC

=> - 80 x 10^-9 C

=> Charge density on each disk, = q / R^2

=> - 80 x 10^-9 / ( * 0.055^2)

=> - 8.422 x 10^-6 C/m^2

Hence;

Electric field due to a charged disk:

E =   /(2 o) { 1 - ( 1 / [1 +(R^2/z^2)] }

A)

At the midpont between two disks, Enet = 0, since the

electric fields due to both disks are equal and opposite.

B)

Electric field due to left disk: ( z = 0.05 m )

E1 =   /(2 o) { 1 - ( 1 / [1 +(R^2/z^2)] }

=> 8.422 x 10^-6 /(2 * 8.854 x 10^-12) { 1 - ( 1 / [1 +(0.055^2/0.05^2)] }

=> 1.557 x 10^5 N/C

Electric field due to right disk: ( z = 0.19 - 0.05 m )

E1 =   /(2 o) { 1 - ( 1 / [1 +(R^2/z^2)] }

=> 18.422 x 10^-6 /(2 * 8.854 x 10^-12) { 1 - ( 1 / [1 +(0.055^2/0.18^2)] }

=> 2.1 x 10^4 N/C

So;

Enet = E1 - E2

=> 1.557 x 10^5 - 2.1 x 10^4

=> 1.347 x 10^5 N/C (Approx.)

Related Questions

Navigate

• Browse (All)
• Browse M
• Subjects

---