In the classical model of the hydrogen atom, the electron revolves around the pr
ID: 1651407 • Letter: I
Question
In the classical model of the hydrogen atom, the electron revolves around the proton with a radius of r = 0.53 times 10^-10m. The magnitude of the charge of the electron and proton is e = 1.6 times 10^-19C a) What is the magnitude of the electric force between the proton and the electron? b) What is the magnitude of the electric field due to the proton at r? What is the ratio of the magnitudes of the electrical and gravitational force between the electron and proton? Does the result depend on the distance between the proton and the electron? d) From the results of your calculation in (b), explain why electrical forces do not influence the motion of planets.Explanation / Answer
A] By coloumbs law, F =kq1q2/r^2
= 9e9*1.6e-19*1.6e-19/0.53e-10^2
= 8.2*10^-8 N
b] electric field = kq/r^2 = 9e9*1.6e-19/0.53e-10^2
= 5.13*10^11 N/C
c] Fe/Fg = [kq1q2/r^2]/[Gm1m2/r^2] = 9e9*1.6e-19*1.6e-19/[6.67e-11*1.67e-27*9.1e-31]
= 2.27*10^39
It is independent of distance
d] The charges of planets and sun are neutral but masses are very high.