Please solve both Qs correctly. Thank you. A 12 CM-diameter cylinder contains ar
ID: 1652991 • Letter: P
Question
Please solve both Qs correctly. Thank you.
A 12 CM-diameter cylinder contains argon gas at 10 atm pressure and a temperature of 40 degree C. A piston can slide in and out of the cylinder. The cylinder's initial length is 23 ?. 2300 J of heat are transferred to the gas, causing the gas to expand at constant pressure. What is the final temperature of the cylinder? Express your answer to two significant figures and include the appropriate units. T_final = Value Units What is the final length of the cylinder? Express your answer to two significant figures and include the appropriate units. I_final = Value UnitsExplanation / Answer
Ideal gas law: PV = nRT
Specific heat energy: Q = nCT (Temperature is in Kelvin)
Molar specific heat at constant pressure for argon: C = 20.85 J/molK
Q = 2300 J
R = 8.314 J/molK
P = 10 atm = [ 10 * 101325 ] = 1013250 Pa
Ti = 40°C = 313.15 K
Vi = Lr^2 = 0.23**0.06^2 = 0.0026 m^3
To get the change in temperature, find number of moles: n = PVi/RTi = 1.012 mol
Find change in temperature: T = Q/nC = 109.02 K
==> Tf = 422.17 K
Find final volume: Vf = nRTf/P = 0.003506 m^3
==> Lf = Vf/0.06^2 = 0.31 m = 31 cm