Can someone show and explain to me how the answer key got it\'s answers? I don\'
ID: 1653086 • Letter: C
Question
Can someone show and explain to me how the answer key got it's answers? I don't understand and I want to chat with you in the comments if I need more of an explanation.4. Shown at right is a large positive point charge +0 surrounded by lines (surfaces) of constant potential. Assume that V=0 at a. How much work must be done on a proton to move it. S, (i). (2 pts) .from point C to point D along the direct path S,? D. 200. eV E. 320. eV F. 400 eV +400. V A. zero B. 100. eV C. 173 ev G. insufficient information +200. V (ii. pt from point C to point D along the roundabout path S2? A. zero B. 100. eV C. 173 eV D. 200. eV E. 320. e F. 400 eV G. insufficient information iii. ( pt ...from point B to point C? A. zero B. 100. ev C. 173 eV D. 200. eV E. 320. eV F. 400 eV G. insufficient information 100. V (iv). ( l pt.) form extremely far away (r-e) to point E? A. zero B. 100. ev C. 173 eV D-200. eV E. 320. ev F. 400 eV G. insufficient information b. (1 pt.) 0 creates an electric field at point B that points in which direction? A. toward point A B. no field C. toward point C D. toward point D E. toward point E F. out of the page c. (1 pt.) If you released an electron at point B, in which direction would it feel a force? A. toward point A B. no force D. toward point D E. toward point E F. out of the page C. toward point C d. (4 pts.) If the +300-volt equipotential surface is located 100 crn away from the point charge +Q, calculate the charge Q:
Explanation / Answer
Given, large chargfe +Q and circles about it are lines of equip[otential surfaces]
i) work done on a proton to move it from C to D is
(Vd - Vc)q [ q is charge on proton, Vis potential at the point) this is independent of the path as conservative force's work just depends on initial and final positions]
W = 1.6*10^-19(400-200) = 3.2*10^-17 J = 200 eV
Option D
ii) work done on a proton to move it from C to D is
(Vd - Vc)q [ q is charge on proton, Vis potential at the point) this is independent of the path as conservative force's work just depends on initial and final positions]
W = 1.6*10^-19(400-200) = 3.2*10^-17 J = 200 eV
Option D
iii) as B and C are at same potential, work done on proton to move it from B to C = 0 J
optinoa A
iV) From extremely far away to point E
W = 1.6*10^-19*200 = 3.2*10^-17 J = 200 eV
option D