Course Home MasteringPhysics: CH 24 HW × Physics question l Chegg.com × c Secure

Question

Course Home MasteringPhysics: CH 24 HW × Physics question l Chegg.com × c Secure l https://session. masteringphysics.com/myct/itemview?assignmentProblemID-81 3884 10&offset;=next https://webmail.psu. https://www1 onpat. https://psu instruct. https://cmspsu.edu/ https:// w youtub ehttps://app.gramma. https://www. stor org https://enc ed.gov/ https: mail.google. » CH24 HM Problem 24.28 e pravious 9 of 15 | next Problem 24.28 Part B A thin, horontal, 12-cm-diameter copper plate is charged to -32nC, Assume that the e ectrons are uniformiy distibuted on the surface What is the direction of the electric ield 0.1 mm above the center of the top surtace of the plate? away from the piate toward the plate Bubmit My Answers give Up Part C What is the atrength of the electr c field at the plate's center or mass? Expross your answer as an intoger and include the appropriate units. EValue Submit Part D what i8 the 8trength of the 0lectric field 0.1 mm below the center of the bottom 8urface of the pate? Expross your answer to two significant figures and include the appropriate units. BValue Units Submit My Answ Gha Up Part E What is the direction of the elecric iekd 0.1 mm below the ceter of the bottom surface of the plate? away from the plate toward the plane Submit

Explanation / Answer

thin horizontal coipper plate
diamtere, d = 12 cm
radius r = 0.06 m

charge, q= -3.2 nC = -3.2*10^-9 C

B. 0.1 mm abov e the surface of charged plate, the electric field is towards the plate ( as it is -vely charged)
C. Electric field at center of mass of plate = 0 [ as electric field inside conductors is 0]
D. Electric field 0.1 mm below the plate
   E = k*q*2*pi[1 - z/sqroot(z ^2 + R^2)]/piR^2
   where z = 0.1*10^-3 m
   E = 2*8.98*10^9*(-3.2*10^-9)[1 - 0.1*10^-3/sqroot((0.1*10^-3)^2 + 0.06^2)]/0.06^2
   E = 15937.837 V/m towards the plate
E. Direction, towads the plate

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---