For the configuration shown in the figure below, suppose a = 5.00 cm, b = 20.0 c

Question

For the configuration shown in the figure below, suppose a = 5.00 cm, b = 20.0 cm, and c = 25.0 cm. Furthermore, suppose the electric field at a point 16.0 cm from the center is measured to be 4.00 times 10^3 N/C radially inward and the electric field at a point 50.0 cm from the center is of magnitude 247 N/C and points radially outward. From this information, find the following. (Include the sign of the charge in your answer.) (a) the charge on the insulating sphere C (b) the net charge on the hollow conducting sphere C (c) the charge on the inner surface of the hollow conducting sphere C (d) the charge on the outer surface of the hollow conducting sphere C

Explanation / Answer

a) We know that,

phi = E A = Q/e0

Q = E A e0 = E r^2/k

Q = 2 x 4000 x 4 x 3.14 x 0.16^2 x 8.85 x 10^-12 = -11.4 x 10^-9 C

Hence, Q = -22.8 x 10^-9 C

b)For this

Q = E A e0

Q = 247 x 4 x 3.14 x 0.5^2 x 8.85 x 10^-12 = 6.86 x 10^-9

Hence, Q = 6.86 x 10^-9 nC

c)The charge here will be = + 22.8 nC

Q = 22.8 x 10^-9 C

d)The charge here will be:

Q = -22.8 nC + 6.86 nC = -4.54 nC

Hence, Q = -15.94 x 10^-9 C

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