Please answer each part of this question with the concept needed to solve it and
ID: 1656197 • Letter: P
Question
Please answer each part of this question with the concept needed to solve it and explain how to do it in detail
1. Consider the Power (energy/second) hitting the barrels. T/F: The total amount of power hitting barrel #1 is the same as the total amount hitting barrel #2.
2. Using classical theory, how does the amount of power (energy/second) hitting the barrels compare for barrel #1 and barrel #2? Explain your reasoning.
3. Now use the quantum (photon) theory and relate how much power (energy/second) is hitting barrel #1 versus barrel #2.
4. The next few problems reconcile these two theories: How does the amount of energy in each photon hitting barrel #1 compare to the amount in each photon hitting barrel #2?
5. How does the number of more photons hitting barrel #1 per second compare to the number of photons hitting barrel #2 per second?
6. From the picture you can see that (wavelength of #2) = 3/5 (wavelength of #1). If there are 3,000,000 photons per second hitting barrel #2, how many photons are hitting barrel #1 per second? (use 3 SigFigs in the form of #.##E#)
7. Explain your understanding of how the wave and photon models can agree in this experiment, but not for the photoelectric effect. In your view, what is the key difference between these two situations that allows the photoelectric experiment to distinguish the photon model from the wave model?
#2 #3Explanation / Answer
a. The total amount of power hitting the barrel 1 is same as barrel two because their amplitudes are the same
so this statement is true
b. given the diagram, the amplitude of the tho waves is the same, waves impinging on cylinder #1 and #2.
but their frequencies are different
From classical theory, power is proportional to amplitude squared
So from classical theory, both the cylinders are recieving the same power
c . by using quantum theorey, the photons impinging cylyder 2 are having higher energy , because of higher frequency of the EM wave
but number of photons in each light beam is decided by the intensity of light ( the amplitude of the light), which is same for both the waves, so cylinder 2 is recieving more power than cylinder 1
d.amount of energy in each photon hitting barreel 2 is more than tha tof barrel 1 because of higher frequency