I just need to know how to do the second part of the problem LAB 5 REPORT 87 5.
ID: 1656702 • Letter: I
Question
I just need to know how to do the second part of the problem LAB 5 REPORT 87 5. The slope A of your best-fit line on the force vs acceleration graph should be equal to the mass of the cart and force probe (in kg), if force and acceleration truly are proportional. How does the slope value compare with the mass value? Assuming that the mass m measured on the balance is the true value, calculate the percent error in your determination of the slope A. Discuss possible sources of measurement error. Ya By Newton's second lauw, F-mo So, m: Fa, which is nothing but thu pe So Slope: mass (5.3) Percent error = mm × 100% 0 acceeration (m/s)Explanation / Answer
According to Newton's 2nd law, the applied force is given by:
F = ma
where a is the acceleration and m is the mass
this is of the form, y = Ax + c
where A is the slope of the y vs x graph and c is the y intercept.
so, if one were to plot force vs acceleration, the slope of that curve will be: A = mass
plot the graph to graphically obtain the mass of the body.
Now, another way of truly determining the mass of the body is by actually (and directly) measuring the mass on a measuring scale.
compare the value of the mass obtained from the graph with this actual measuring scale value.
This is done by finding the percentage error of the value obtained from the graph with the actual value. It is given by:
P = ([m - A]/m) x 100%
where A is the value from the graph and m is the measuring scale value.