I have the answer, 7.3 correct for part A. can you please assist with Part B? I

Question

I have the answer, 7.3 correct for part A. can you please assist with Part B? I am doing something wrong.

HYS 2424 E 2017] Homework 4 Homework 4Begin Date:9/12 2017 12:00:00 AM -Due Date: 9/25/2017 11:59:00 PM End Date: 9/25 2017 11:59:00 PM Problem! : Consider 3 resistors with resistances 1.15 × 102 . 2.9 ks2, and 4.3 kS2 1700 22 12 Part (a) what would be their resistance, Rs. In kilohms, Ifthey were connected in series? Numeric A numeric value is expected and not an expression.. R, Part (b) What would be their resistance, Rp in ohms, if they were connected in parallel? Numeric :A numeric value is expected and not an expression. 0095 Problem 2: Consider the three-resistors R,-17 , R,-54 , and R3-89 in the configuration shown in the figure. A potential difference AV 3.5 V is applied between A and B. A R1 7 R3 Otheexpertta.com

Explanation / Answer

b] Resistors R2 and R3 are connected in parallel and so their equivalent resistance will be given by:

1/Req = 1/2900 + 1/4300

=> Req = 1731.944 ohms

this is now in series with 115 ohms resistor. So, the final resistance of the circuit will be:

Rp = 115 + 1731.944 = 1846.944 ohms.

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