Images not uploading... Vx(m/s) 12 | --------------------------- 10 | / \\ 8 | /
ID: 1659634 • Letter: I
Question
Images not uploading...
Vx(m/s)
12 | ---------------------------
10 | /
8 | /
6 | /
4 | /
2 | /
|/__________2_____3____4__________6___________8 t(s)
The line starts at origin. extends upward to (3,12) flat from (3,12) to (6,12), then neg slope to (8,0)
shows the velocity graph of a 2.2 kg object as it moves along the x-axis.
What is the net force acting on this object at t = 1 s ? At 4s? At 7?
Explanation / Answer
at T=1
a = (12 m/s) / (3s)
at T = 1 the slope is 12/3 = a = 4 m/s2
F = m*a
F = 2.2*4
F = 8.8 N
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at T= 4
a = 0
F = 0
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at T=7
a = -12 m/s / 2 s
at T = 7 the slope is -12/2 = a = -6 m/s2
F = 2.2*(-6)
F = -13.1 N
negative means opposite to direction of motion