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IlI YouTube to mp3 Home:Alabe.versity LOON-Blackboard Learm Google Youlube Yahoo Netfix Apple Apple Dianey ESPw Bing Yahos Cloud Facebook Twiher Wipedia e2 and over a time irt.. Chapter 2,serto A student drove to the university from her home and noted that the odometer on her car increased by 1.0 km. The trip took 17 0 m n. (a) What was her average speed? km/h distance from her home to the university is 10.3 km in a direction 25.0° south of east, what was her average velocity? km/h (25 S of E) e) If she returned home by the same path 7 h 30 min after she left, what were her average speed and velocity for the entire average speed km/h km/h 16. o 2 20 points 2.5.034 XP My Notes O Ask Your An express subway train passes through an underground station. It enters at t tyrough. The station in 200 m long 0 with an initial velocity of 18.o m/s and decelerates at a rate of 0.150 m/s? as it goes (a) How long is the nose of the train in the station? (b) How fast is it going when the nose leaves the station (c) If the trar, 130 m long, at what time t does the end of the tron leave the station, (d) What is the velocity of the end of the train as in leaves m/s

Explanation / Answer

a) Distance travelled = 14 km

Time taken = 17 min = 17/60 hr

Average speed = Distance/time = 14/(17/60) = 49.41 km/hr

b) Displacement = 10.3 km

Average velocity = Displacement/time = 10.3/(17/60) = 36.35 km/hr

c)Total distance travelled = 2 x 14 = 28 km

Time = 7 hr 30 min = 7 + 30/60 hr = 7.5 hr

average speed = 28/7.5 = 3.73 km/hr

d) On returning to the same place,

displacement = 0

So,

average velocity = 0 km/hr

Hope this helps :)

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