Constants ongin O, due o charge are aced as shown in the figure The el c nc teld

Question

Constants ongin O, due o charge are aced as shown in the figure The el c nc teld att 122 m, and r2 1.51 m. Q Y1 and qual to 270 N direc d aan angle 36 rom the negati in the 10 point charge Q 410 nC and two unknown pont charges h and quadrant. The distances of charges from the origin are r 2.3m, is th Use R! R," Ro R as notations tr the electre telds of charges Q nd net held respectively 91 30° 2 92 Part A What is the magnitude of the electric field dus to the point charge Q at the crigin 0? EoValue Units Subrnit

Explanation / Answer

Part a.) Electric field due to charge Q,

Eq=kQ/r2

=9×(10)9×(-410)/5.29

Eq=6.97×1011 N/C answer.

part b.) The direction of electrical fied due to point charge q1 is in positive x-axis. (From the answer part c)

part c.)in the given question the electric field due to point charge q1 is 270 so,

270=kq1/r12

270=9×109×q1/(-j1.22)2

270=-q16.0467×109

q1=-0.4465nC answer.

part d.) The direction of electric field due to point charge q2 is in positive y-axis. (From the answer of part e).

part e.) By point charge q2 the electrical field is 270 N/C so,

270= 9×109×q2/(1.54)2

q2=71.148nC answer.

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