Blocks 1 and 2 of masses m 1 and m 2 areconnected by light string. Block m 1 is

Question

Blocks 1 and 2 of masses m1 and m2 areconnected by light string. Block m1 is behindblock m2   These blocks are further connectedto block of mass M by another light string that passes over apulley of negligible mass and friction. Blocks 1 and 2 movewith constant velocity down inclined plane which make an angle with horizontal. Kinetic frictional force on block 1is f and that on block 2 is 2f Express your answers to each of the following in terms ofm1, m2, g, and f Determine the coefficient of kinetic friction between inclinedpland and block 1 Determine value of suspended mass M that allows blocks 1 and 2to move with constant velocity down plane The string between blocks 1 and 2 is now cut. Determineacceleration of block 1 while it is on inclined plane Blocks 1 and 2 of masses m1 and m2 areconnected by light string. Block m1 is behindblock m2   These blocks are further connectedto block of mass M by another light string that passes over apulley of negligible mass and friction. Blocks 1 and 2 movewith constant velocity down inclined plane which make an angle with horizontal. Kinetic frictional force on block 1is f and that on block 2 is 2f Express your answers to each of the following in terms ofm1, m2, g, and f Determine the coefficient of kinetic friction between inclinedpland and block 1 Determine value of suspended mass M that allows blocks 1 and 2to move with constant velocity down plane The string between blocks 1 and 2 is now cut. Determineacceleration of block 1 while it is on inclined plane

Explanation / Answer

for m1: = f/(m1gcos) for M: T - Mg = 0, so tension T = Mg for m1 + m2: (m1 + m2)gsin - T - f - 2f = 0 T = (m1 + m2)gsin - 3f M = T/g = (m1 + m2)sin -3f/g acceleration of m1 is a m1gsin - f = m1a a = gsin - f/m1

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