Blocks (mass 6.50 ) and (mass 15.00 ) move on a frictionless, horizontal surface
ID: 1904651 • Letter: B
Question
Blocks (mass 6.50 ) and (mass 15.00 ) move on a frictionless, horizontal surface. Initially, block is at rest and block is moving toward it at 10.0 . The blocks are equipped with ideal spring bumpers. The collision is head-on, so all motion before and after the collision is along a straight line. Let be the direction of the initial motion of . Find the maximum energy stored in the spring bumpers and the velocity of each block at that time. Find the maximum energy. Find the velocity of . Find the velocity of . Find the velocity of each block after they have moved apart. Find the velocity of . Find the velocity of .Explanation / Answer
(a)
By conservation of momentum:
6.5*10=V*(6.5+15)
V = 3.0233 m/s
Initiial energy ;
KE1 = 0.5*6.5*10^2 = 325 J
Final energy:
KE2 = 0.5*(6.5+15)*3.023^2 =98.259 J
Maximum energy in spring = KE1 - KE2 = 226.741 J
(b)
By conservation of momentum:
6.5*10=V*(6.5+15)
V = 3.0233 m/s
Velocity of 6.5 = 3.0233 m/s
(c)
By conservation of momentum:
6.5*10=V*(6.5+15)
V = 3.0233 m/s
Velocity of 15 = 3.0233 m/s
(d)
VA2= [(mA-mB)/(mA+mB)]*VA1
=[(6.5-15)/(6.5+15)] *10
= -3.955 m/s
(e)
VB2= [(2*mA)/(mA+mB)]*VA1
=[2*6.5/(6.5+15)] *10
=6.0465 m/s