Please help me solve this problem!!!!! Thanks so Much in advance Please help me

Question

Please help me solve this problem!!!!!

Thanks so Much in advance

Please help me answer this question!! THANKS SO MUCH INADVANCE!!

a) A sample of an ideal gas is at a temperature of 320 K. The rmsmolecular speed at this temperature is measured as 1631 m/s.Calculate the mass of a molecule of this gas.

b) A sample of an ideal gas is at a temperature of 320 K. The rmsmolecular speed at this temperature is measured as 1631 m/s.Calculate the mass of a molecule of this gas.

c) The initial pressure in an ideal gas is 1.40 atm when itstemperature is 299 K. The temperature is increased to 315 K and thevolume is increased to 1.29 times its initial value. Calculate thefinal pressure

Explanation / Answer

a) A sample of an ideal gas is at a temperature of 320 K. Therms molecular speed at this temperature is measured as 1631 m/s.Calculate the mass of a molecule of this gas.
rms velocity , u = (3RT/M ) Given u = 1631 m / s Temperature , T = 320 K R = gas constant = 8.314 J/ mol . K Molar mass of the gas molecule , M = 3RT / u 2                                                       = 3 * 10^-3 Kg / mol
b) A sample of an ideal gas is at a temperature of 320 K. The rmsmolecular speed at this temperature is measured as 1631 m/s.Calculate the mass of a molecule of this gas. rms velocity , u = (3RT/M ) Given u = 1631 m / s Temperature , T = 320 K R = gas constant = 8.314 J/ mol . K Molar mass of the gas molecule , M = 3RT / u 2                                                       = 3 * 10^-3 Kg / mol

c) The initial pressure in an ideal gas is 1.40 atm when itstemperature is 299 K. The temperature is increased to 315 K and thevolume is increased to 1.29 times its initial value. Calculate thefinal pressure From gas law PV = nRT PV / T = P' V' / T' P = 1.4 atm V ' = 1.29 V T = 299 K T' = 315 K P' = ? P' = PVT' / TV'     = 1.143 atm

                                                      = 3 * 10^-3 Kg / mol
b) A sample of an ideal gas is at a temperature of 320 K. The rmsmolecular speed at this temperature is measured as 1631 m/s.Calculate the mass of a molecule of this gas. rms velocity , u = (3RT/M ) Given u = 1631 m / s Temperature , T = 320 K R = gas constant = 8.314 J/ mol . K Molar mass of the gas molecule , M = 3RT / u 2                                                       = 3 * 10^-3 Kg / mol

c) The initial pressure in an ideal gas is 1.40 atm when itstemperature is 299 K. The temperature is increased to 315 K and thevolume is increased to 1.29 times its initial value. Calculate thefinal pressure From gas law PV = nRT PV / T = P' V' / T' P = 1.4 atm V ' = 1.29 V T = 299 K T' = 315 K P' = ? P' = PVT' / TV'     = 1.143 atm

Given u = 1631 m / s Temperature , T = 320 K R = gas constant = 8.314 J/ mol . K Molar mass of the gas molecule , M = 3RT / u 2                                                       = 3 * 10^-3 Kg / mol

c) The initial pressure in an ideal gas is 1.40 atm when itstemperature is 299 K. The temperature is increased to 315 K and thevolume is increased to 1.29 times its initial value. Calculate thefinal pressure From gas law PV = nRT PV / T = P' V' / T' P = 1.4 atm V ' = 1.29 V T = 299 K T' = 315 K P' = ? P' = PVT' / TV'     = 1.143 atm

                                                      = 3 * 10^-3 Kg / mol

c) The initial pressure in an ideal gas is 1.40 atm when itstemperature is 299 K. The temperature is increased to 315 K and thevolume is increased to 1.29 times its initial value. Calculate thefinal pressure From gas law PV = nRT PV / T = P' V' / T' P = 1.4 atm V ' = 1.29 V T = 299 K T' = 315 K P' = ? P' = PVT' / TV'     = 1.143 atm

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