Question
In the figure below the switch S is initially in position "a". Given, R1 = R2 = R3. Neglect the internal resistance of the battery. What happens to the current through R3 when the switch is moved to the open position "b"?. The current through R3 increases to twice its original value. The current through R3 is reduced to one-half its original value. The current through R3 remains the same. The current through R3 decreases to two-thirds its original value. The current through R3 increases to throw-halves its original value. What happens when switch S is moved to position "c", leaving R2 and R3 parallel? The current through R3 increases. The current through R2is half what it was with R1 in the circuit. The current through R2 remains the same as when R was in the circuit. The current through R3 decreases. The current through R2 and R3 are now the same.
Explanation / Answer
005 question before switch, Req =(R1+R2)*(R3)/[R1+R2+R3]= 2R1/3 total currect through R3 is I0 = V/R3 = V/R1 after switch, I = V/R3 = V/R1 answer: 3 : after switch to b, the currect remain thesame 006: I2 = V/R3 = V/R1 answer: 5, the currect through R2 is the same asR3 now answer: 5, the currect through R2 is the same asR3 now