A 56 kg skier skis directly down africtionless slope angled at 15° to the horizo
ID: 1664756 • Letter: A
Question
A 56 kg skier skis directly down africtionless slope angled at 15° to the horizontal.Assume the skier moves in the negative direction of an xaxis along the slope. A wind force with componentFx acts on the skier. (a) What is Fx if themagnitude of the skier's velocity is constant?1 N
(b) What is Fx if the magnitude of the skier'svelocity is increasing at a rate of 2.0m/s2?
2 N
(c) What is Fx if the magnitude of the skier'svelocity is increasing at a rate of 4.0m/s2?
3 N (a) What is Fx if themagnitude of the skier's velocity is constant?
1 N
(b) What is Fx if the magnitude of the skier'svelocity is increasing at a rate of 2.0m/s2?
2 N
(c) What is Fx if the magnitude of the skier'svelocity is increasing at a rate of 4.0m/s2?
3 N
Explanation / Answer
a)The skier have a constant velocity So the net force act on him is zero Fw=P*sin15=142(N) b)We have that F=ma so ma=mg*sin15-Fw so Fw=m(gsin15-a)=30(N) c) the maximum acceleration of the skier is g sin15 = 2,7 The wind force have the direction so as the velocity magnitude isdecrease so the acceleration alway lower than 2,7 The answer is It is impossible.