Charge q 1 = 9.20 x 10 -10 C is at the origin and charge q 2 = 8.91 x 10 -9 C ha

Question

Charge q1 = 9.20 x 10-10 C is at the origin and charge q2 = 8.91 x 10-9 C has coordinates x = 40.8 cm,y = 0. Find the coordinates of a field point whereE = 0. Charge q1 = 9.20 x 10-10 C is at the origin and charge q2 = 8.91 x 10-9 C has coordinates x = 40.8 cm,y = 0. Find the coordinates of a field point whereE = 0. Charge q1 = 9.20 x 10-10 C is at the origin and charge q2 = 8.91 x 10-9 C has coordinates x = 40.8 cm,y = 0. Find the coordinates of a field point whereE = 0. Charge q1 = 9.20 x 10-10 C is at the origin and charge q2 = 8.91 x 10-9 C has coordinates x = 40.8 cm,y = 0. Find the coordinates of a field point whereE = 0. q1 = 9.20 x 10-10 C q2 = 8.91 x 10-9 C

Explanation / Answer

As the two charges are on the x-axis and the two charges arelike charges, therefore the electric field is zero on the x-axisand the point lies in between the charges. let the point is at a distance of x from the origin,    then for the net field to bezero, the magnitudes of the two electric fields should beequal.    Therefore kq1/x^2 =kq2/(0.408-x)^2    or (9.2*10^-10C)/x^2= (8.91*10^-9C)/(0.408-x)^2    or (0.408-x)^2 =9.685 x^2    or 0.408 - x =3.11x    or 4.11x =0.408    or x =0.09927m      = 9.93cm therefore the electric field is zero at distance 9.93cm fromteh origin.

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