Hey how would I solve this? An electron is released from rest at the negative pl

Question

Hey how would I solve this? An electron is released from rest at the negative plate of aparallel plate capacitor and accelerates to the positive plate. Theplates are separated by a distance of 1.4 cm, and the electricfield within the capacitor has a magnitude of 2.2 x 106V/m. What is the kinetic energy of the electron just as it reachesthe positive plate? Thanks! Hey how would I solve this? An electron is released from rest at the negative plate of aparallel plate capacitor and accelerates to the positive plate. Theplates are separated by a distance of 1.4 cm, and the electricfield within the capacitor has a magnitude of 2.2 x 106V/m. What is the kinetic energy of the electron just as it reachesthe positive plate? Thanks!

Explanation / Answer

We know that           KE = q V                 = q E d                 = 1.6 x 10-19 C * 2.2 x 106 V/m *1.4 x 10-2 m    =4.928 x 10-15 J

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