Please help me to have the fianl answer. Thx ASAP 1. An electron is shot into on

Question

Please help me to have the fianl answer. Thx ASAP
1. An electron is shot into one end of a solenoid. As itenters the uniform magnetic field within the solenoid, its speedis 840 m/s and its velocityvector makes an angle of 30° with the central axis of thesolenoid. The solenoid carries 4.5 A and has 8000 turns along its length.How many revolutions does the electron make along its helical pathwithin the solenoid by the time it emerges from the solenoid'sopposite end? (In a real solenoid, where the field is not uniformat the two ends, the number of revolutions would be slightly lessthan the answer here.) rev

1. An electron is shot into one end of a solenoid. As itenters the uniform magnetic field within the solenoid, its speedis 840 m/s and its velocityvector makes an angle of 30° with the central axis of thesolenoid. The solenoid carries 4.5 A and has 8000 turns along its length.How many revolutions does the electron make along its helical pathwithin the solenoid by the time it emerges from the solenoid'sopposite end? (In a real solenoid, where the field is not uniformat the two ends, the number of revolutions would be slightly lessthan the answer here.)

Explanation / Answer

Let the length of the solenoid be L. time of flying. v*cos30*T=L. so T=L/vcos30 In the spining motion of the electron we have. mv^2/r=Bqv. so v/r=Bq/m.=. so number of revolution. N=T*/2=L/vcos30 *Bq/m2=LBq/vcos30*m*2. We have B=I0*n. so B*L=I0*N0 while N0 be number of turns (8000). N=I0*N0*q/vcos30m2.=1,74e6(rev)

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---