I have no idea how to go about solving this problem. Any help wouldbe appreciate

Question

Explanation / Answer

x.Xtyle="margin-top: 0px; margin-right: 0px; margin-bottom: 0px; margin-left: 0px; padding-top: 0px; padding-right: 0px; padding-bottom: 0px; padding-left: 0px; list-style-type: none; list-style-position: initial; list-style-image: initial; " />   from the given problem let the surface of the water will be the position 1 and the exit of the hose    be the position 2 then we can see that the pressures are equal so we get    P1 = P2    from the bernoulis equation we get    (1 / 2) v12 + g y = (1 / 2) v22    as at the surface of the water the speed is zero we can write v1 = 0 so that    v2 = (2 g y) (b)    the siphon will stop working when v2 = 0 m / s or y = 0 (c)    at point A we get    PA + g (h + y) + (1 / 2) vA2 = Po + (1 / 2) v22    as vA = v

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects