A projectile is thrown upward at 24.0degree with the verticaland returns to the

Question

A projectile is thrown upward at 24.0degree with the verticaland returns to the horizontal ground 12.5 a later with no airdrag A) how fast was it thrown? B) How far from its original position did it land? C) how high above its original position did it go? A projectile is thrown upward at 24.0degree with the verticaland returns to the horizontal ground 12.5 a later with no airdrag A) how fast was it thrown? B) How far from its original position did it land? C) how high above its original position did it go?

Explanation / Answer

90-24 = 66 degrees with the horizontal

a)
at the highest point ( half the time) , the y velocity is0... Vy = Voy + at 0 = Vosin66 - 9.8(12.5/2) Vo = 67 m/s

b)
x = VoX*T x = 67cos66*12.5 x = 340.6 m

c)
Y = VoY*T - 1/2at^2 Y = 67sin66(12.5s /2) - 4.9(12.5/2)^2 Y = 191 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---