Please somebody help me to solve this problem: The questions say,A charge q is a

Question

Please somebody help me to solve this problem: The questions say,A charge q is at x = 2 m and a secondcharge -q is at x = -2 m, I was asked to find (a) the electricfield on the x axis at an arbitrary point where x > 2 m, and (b)the limiting form where x>> 2 m. Thank you all for your support. Please somebody help me to solve this problem: The questions say,A charge q is at x = 2 m and a secondcharge -q is at x = -2 m, I was asked to find (a) the electricfield on the x axis at an arbitrary point where x > 2 m, and (b)the limiting form where x>> 2 m. Thank you all for your support.

Explanation / Answer

First charge q1 = +q (at x=2m) Second charge q2 = -q (at x=-2m) (a) Now we have to find  the electric field on the xaxis at an arbitrary point where x>2 m which is at the right hand side of these two charges q1 &q2. So electric field due to first charge (E1) & that due tosecond charge (E2) are in opposite directions. we know that E1 = kq/(x-2)2 (along rightside)
                     &  E2 = -kq/(x+2)2 (along left side)                          where k = electrostatic constant =1/40 so resultant electric field E = E1 - E2                                        =2kq(x2+4)/(x2-4)2   [along right side] (b) Now we have to find  the electric field on the xaxis at an arbitrary point where x>>2 m which is at the right hand side of these two charges q1 &q2. resultant electric field E =2kq/x2    (along right side)
[Here x>>2 , so x2>>>>4,weneglect 4 in comparison with x2] Now we have to find  the electric field on the xaxis at an arbitrary point where x>>2 m which is at the right hand side of these two charges q1 &q2. resultant electric field E =2kq/x2    (along right side)
[Here x>>2 , so x2>>>>4,weneglect 4 in comparison with x2]

  

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