I have to find the position, velocity, acceleration, momentum, andforce for this

Question

I have to find the position, velocity, acceleration, momentum, andforce for this system (ie. center of mass) in function form,and then evaluate at t=1. The information given are:
mass1= 5kg mass2=2kg mass3=3kg
x1(t)=t3+2t-3, y1(t)=t2+1
x2(t)=3t+4, y1(t)=t4-2t+3
x3(t)=t2-4t+1, y3(t)=t3+2t-1
I want to see how other people do this problem.
Thank You

mass1= 5kg mass2=2kg mass3=3kg
x1(t)=t3+2t-3, y1(t)=t2+1
x2(t)=3t+4, y1(t)=t4-2t+3
x3(t)=t2-4t+1, y3(t)=t3+2t-1
I want to see how other people do this problem.
Thank You

Explanation / Answer

1)x1(t) = t3+2t-3, y1(t) = t2 + 1 v1x = (dx1(t)/dt) = 3t2 +2,v1y = (dy1(t)/dt) = 2t a1x = (dv1x/dt) = 6t,a1y =(dv1y/dt) = 2 The resultant position is S = ((x1(t))2 +(y1(t)))1/2 The resultant velocity is v = (v1x2 +v1y2) The resultant acceleration is a = (a1x2 +a1y2) The position,velocity and acceleration are evaluated at t = 1s. The momentum and force for this system are P = m1v and F = m1a 2)x2(t) = 3t + 4,y1(t) = t4 -2t+3 Similarly,v2x = 3,v2y = 4t3 -2 and a2x = 0,a2y = 12t2 3)x3(t)=t2-4t+1, y3(t)=t3+2t-1 Similarly,v3x = 2t - 4,v3y =3t2 + 2
and a3x = 2,a3y = 6t 3)x3(t)=t2-4t+1, y3(t)=t3+2t-1 Similarly,v3x = 2t - 4,v3y =3t2 + 2
and a3x = 2,a3y = 6t Similarly,v3x = 2t - 4,v3y =3t2 + 2
and a3x = 2,a3y = 6t and a3x = 2,a3y = 6t

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