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Particles of charge +75(Q1), +48 (Q2), and -85(Q3) C are placed in a line. The c

ID: 1683110 • Letter: P

Question

Particles of charge +75(Q1), +48 (Q2), and -85(Q3) C are placed in a line. The center one is .35 m from each of the others. Calculate the net force on each charge due to the other two.
Okay, so that's my problem, and I've been looking at the solution on cramster. This is problem 16.12 from Physics: Principles with Applications (6th) By Giancoli. The formula for the force on +75 by +48 and -85 is: F75= -K(Q1Q2/r122)+K(Q1Q3/r132) My question is: where did the negative sign in front of the first K come from? The same thing occurs in the next two calculations. Negative signs are popping up everywhere. Why?
Okay, so that's my problem, and I've been looking at the solution on cramster. This is problem 16.12 from Physics: Principles with Applications (6th) By Giancoli. The formula for the force on +75 by +48 and -85 is: F75= -K(Q1Q2/r122)+K(Q1Q3/r132) My question is: where did the negative sign in front of the first K come from? The same thing occurs in the next two calculations. Negative signs are popping up everywhere. Why?

Explanation / Answer

I don't have this book and don't know the configuration of these three charges. I think the +x axis is passing through from +75 to +48, then to -83 So, force on +75 due to +48 is repulsive, with direction -x, so the x component of the force is negative, force on +75 due to -85 is attractive, with direction +x, so the x component of the force is positive. K itself is always positive and constant.