Particles A through D have the following rest energies and total energies: Parti

Question

Particles A through D have the following rest energies and total energies: Particle Rest Energy Total Energy A 6E 6E B 2E 4E C 4E 6E D 3E 4E Part A Rank these particles in order of decreasing rest mass. Rank particles from largest to smallest rest mass. To rank items as equivalent, overlap them. Part B Rank these particles in order of decreasing kinetic energy. Part C Rank these particles in order of decreasing speed.
Particles A through D have the following rest energies and total energies: Particle Rest Energy Total Energy A 6E 6E B 2E 4E C 4E 6E D 3E 4E Part A Rank these particles in order of decreasing rest mass. Rank particles from largest to smallest rest mass. To rank items as equivalent, overlap them. Part B Rank these particles in order of decreasing kinetic energy. Part C
Particles A through D have the following rest energies and total energies: Particle Rest Energy Total Energy A 6E 6E B 2E 4E C 4E 6E D 3E 4E Part A Rank these particles in order of decreasing rest mass. Rank particles from largest to smallest rest mass. To rank items as equivalent, overlap them. Part B Rank these particles in order of decreasing kinetic energy. Rank these particles in order of decreasing speed. Particle Rest Energy Total Energy A 6E 6E B 2E 4E C 4E 6E D 3E 4E

Explanation / Answer

for particle A

m1gh = 6E

so m1 = 6E/gh

for particle B

m2gh = 2E

m2 = 2E/gh

for particle C

m3gh = 4E

m3 = 4E/gh

for particle D

m4gh = 3E

m4 = 3E/gh

so

m1 > m3 > m4 > m2

b) as total energy = rest energy + kinetic energy

K.E. of A = 0

K.E. of B = 2E

K.E. of C = 2E

K.E. of D = E

so K.E.B = K.E.C > K.E.D > K.E.A

c)K.E. = m*v^2/2

so Va = 0

Vb = sqrt(4E/m2) = sqrt(2gh)

Vc = sqrt(4E/m3) = sqrt(gh)

Vd = sqrt(2E/m4) = sqrt(2gh/3)

so Vb > Vc > Vd > Va

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