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Particle of mass m colides with a second particle of mass m. before the collisio

ID: 1963311 • Letter: P

Question

Particle of mass m colides with a second particle of mass m. before the collision the first particle is moving?
in the x direction with a speed 2v and the second particle is at rest. after the collision, the second particle is moving in the direction 45 degrees below the x axis and with a speed square root 2v
a) find the velocity of the first particle after the collision
b)find the total kinetic energy of the 2 particles before and after the collision
c) is the collision elastic or inelastic justify with math
-show all work..step by step please

Explanation / Answer

Given data Mass of the two particles is m Initial velocity of the first particle is, v1i = 2v Final velocity of the second particle is, v2f = 2v [ cos45o (i) - sin 45o (j)] Magnitude of final velocity of second particle is,                           v2f = 2v [ (1/2 i - 1/2 j ]                                 = 2v (a) From the law of conservation of momentum along x axis, we get          mv1ix + m v2ix = m v1fx + m v2fx                m (2v) + 0 = m v1fx + m 2v cos45o                            v1fx = 2v - 2 v (1/2)                                   = v Along y axis,                             0 = m v1fy + m v2fy                              0 = mv1fy - m2v sin 45o                        v1fy   = 2 v (1/2)                                 = v The velocity of the particle is,                         v1f   = v2 + v2                                 = 2 v ------------------------------------------------------------------------------------------ (b) Total kinetic energy of the particle before collision is,           Ki = 1/2 m (v1i2 + v2i2 )                = 1/2 m (2 v)2                = 2mv2 Total kinetic energy after the collision is,          Kf = 1/2 m (v1f2 + v2f2 )                = 1/2 m [(2 v)2 + (2v )2               = 2mv2 ------------------------------------------------------------------------------------------- (c) From part (b), we can conclude that the energy is conserved. So, it is an elastic collision. Total kinetic energy after the collision is,          Kf = 1/2 m (v1f2 + v2f2 )                = 1/2 m [(2 v)2 + (2v )2               = 2mv2 ------------------------------------------------------------------------------------------- (c) From part (b), we can conclude that the energy is conserved. So, it is an elastic collision. ------------------------------------------------------------------------------------------- (c) From part (b), we can conclude that the energy is conserved. So, it is an elastic collision.