Particle in a box: given the number of carbon atoms, and the wavelength. How do
ID: 1339025 • Letter: P
Question
Particle in a box: given the number of carbon atoms, and the wavelength. How do I find the highest filled orbital, the lowest unoccupied orbital, and the box length. (ex. # of C atoms = 4, wavelength = 508.9nm. HFO = ?, LUO= ?, Box length = ?nm
L=[(h/8mc) (n^2-n^2 )] I believe I need to use this equation to find the box length. I just don't know how to find what the n values are.
this experiment only deals with unbranched hydrocarbons where the number of pi-electrons is equal to the total number of carbons in the system
Explanation / Answer
E = hc/lambda
E = n^2h^2/8mL^2
hc/lambda = 3.91 x 10^-19 J
3.91 x 10^-19 = (3^2-2^2) * h^2/8*9.1x10^-31 * L^2
L = 8.79 x 10^-10 m
4 carbon atom it can be butane butayne , butene
2 atom in n =1
2 atom n = 2
here HFO = 2
LFO = 3