Particle A of charge 7.00 10-4 C is at the origin, particle B of charge -8.00 10
ID: 1704632 • Letter: P
Question
Particle A of charge 7.00 10-4 C is at the origin, particle B of charge -8.00 10-4 C is at (6.00 m, 0) and particle C of charge 2.00 10-4 C is at (0, 4.00 m).(a) What is the x-component of the electric force exerted by A on C?
1 N
(b) What is the y-component of the force exerted by A on C?
2 N
(c) Find the magnitude of the force exerted by B on C.
3 N
(d) Calculate the x-component of the force exerted by B on C.
4 N
(e) Calculate the y-component of the force exerted by B on C.
5 N
(f) Sum the two x-components to obtain the resultant x-component of the electric force acting on C.
6 N
(g) Repeat part (f) for the y-component.
7 N
(h) Find the magnitude and direction of the resultant electric force acting on C. magnitude 8 N
direction 9° above the +x-axis
Explanation / Answer
(a) the x-component of the electric force exerted by A on C is zero N, because the force along Y- axis only.
(b) What is the y-component of the force exerted by A onC ,
Fy = kq1q2/r^2 = 9*10^9*7*10^-4*2*10^-4/16
= 78.75 N
(c) the force exerted by B on C, F = -9*10^9*8*10^-4*2*10^-4 /52
F =- 27.692 N
the magnitude of the force exerted by B on C is -27.692 N.
(d) the x-component of the force exerted by B on C,
Fx = F cas = 27.692cas(33.7)= 23.04 N
(e) the y-component of the force exerted by B on C.
Fy = F sin = -15.36 N
(f) the sum of x components , Fx = 27.689 N +0 N
Fx = 23.04 N
(g ) The sum of y components , Fy = 78.75 N -15.36 N
Fy = 63.38 N
(h) the magnitude F = 67.437 N
the direction = Fy/Fx = 70 degree