Particle A of mass M and speed v moving to the right, strikes particle B of mass
ID: 2120526 • Letter: P
Question
Particle A of mass M and speed v moving to the right, strikes particle B of mass 3M that is moving to the left at speed v5.0. The collision is elastic. In terms of m and v reduced to the simplest form
a) find the total momentum of the system before collision.
b) find the velocities of both particles after collision.
c) find the change in momentum of particle A.
d) find the impulse imparted on particle B.
d) find the velocity of the center of mass of the two particles before the collision?
Explanation / Answer
a)momentum before collision
P = (3M x 5v - M x v)
b)the velocities are
v1 = [(3M - M) x v + 2 x 3M x 5v/(3M + M)]
and v2 = [2 x M x v + (3M - M) x 5v/(3M + M)]
c)change in momentum is
P = M x v1
d)impulse is
P = 3M x v2