Particle A of charge 5.00 10-4 C is at the origin, particle B of charge -7.00 10
ID: 2160750 • Letter: P
Question
Particle A of charge 5.00 10-4 C is at the origin, particle B of charge -7.00 10-4 C is at (5.00 m, 0) and particle C of charge 3.00 10-4 C is at (0, 4.00 m).(a) What is the x-component of the electric force exerted by A on C?
Correct: Your answer is correct. N
(b) What is the y-component of the force exerted by A on C?
Correct: Your answer is correct. N
(c) Find the magnitude of the force exerted by B on C.
Correct: Your answer is correct. N
(d) Calculate the x-component of the force exerted by B on C.
Incorrect: Your answer is incorrect.
Your response differs from the correct answer by more than 100%. N
(e) Calculate the y-component of the force exerted by B on C.
Incorrect: Your answer is incorrect.
Your response differs from the correct answer by more than 10%. Double check your calculations. N
(f) Sum the two x-components to obtain the resultant x-component of the electric force acting on C.
N
(g) Repeat part (f) for the y-component.
N
(h) Find the magnitude and direction of the resultant electric force acting on C.
magnitude N
direction
Explanation / Answer
Distance between A and C is 4 m Distance between B and C is 5 m Formula for force = 9e9 q1q2/r^2 Use 9e9*ax1e-4*b*1e-4 = 90 ab =========================== a) Zero. b) y component of the electric force exerted by A on C 90*5*3 /4^2 = 84.375 N c) The magnitude of the force exerted by B on C. 90*7*3/41 = 46.09 N d) Angle of BC with the x axis 180 – ? and tan ? = 4/5 and hence 180 – ? = 164.8° the x component of the force exerted by B on C. is 46.09cos 164.8 = -44.47 minus shows that it is toward left e). the y component of the force exerted by B on C. 46.09 sin 143.13 = 27.65 N f) Sum the two x components from part (a) and (d) = the resultant x component of the electric force acting along x -axis is -44.47 g) Sum the two y components from part (a) and (d) = the resultant y component of the electric force acting along y -axis is 30 + 12.96 = 112.025 N h) Resultant of -44.47 and 112.025 is = 120.52 N Direction is at angle (90 + f) from the x axis. 120.52 sin f = 112.025 => f = 68.36° (90 + f) = 90 +68.36 = 158.36° from the x axis.